(10-6x)^1/2=(3x+4)^1/2

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Solution for (10-6x)^1/2=(3x+4)^1/2 equation: 


x in (-oo:+oo)

((10-(6*x))^1)/2 = ((3*x+4)^1)/2 // - ((3*x+4)^1)/2

((10-(6*x))^1)/2-(((3*x+4)^1)/2) = 0

(10-6*x)/2-((3*x+4)/2) = 0

(10-6*x)/2+(-1*(3*x+4))/2 = 0

10-1*(3*x+4)-6*x = 0

6-9*x = 0

(6-9*x)/2 = 0

(6-9*x)/2 = 0 // * 2

6-9*x = 0

6-9*x = 0 // - 6

-9*x = -6 // : -9

x = -6/(-9)

x = 2/3

x = 2/3

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